Javascript analogue of Ruby's "any?"
[true, true].every(Boolean)
true
[true, true, false].every(Boolean)
false
[true, true, null].every(Boolean)
false
[true, true, ""].every(Boolean)
false
[].every(Boolean)
true
Written by Alexey Astafyev
Related protips
2 Responses
Hey, man, look here http://underscorejs.org/#any
;) Also a good thing, right?
over 1 year ago
·
Yep. Underscore.js rules!
But this pro tip is just for plain JavaScript.
over 1 year ago
·
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