Running a Cron Job every other week

You can't specify in the cron schedule for the day of week to be divided unlike some of the other schedules, nor can you use the # to get consistent results.

The answer is to use an epxression in cron command:

0 10 * * 1 [ `expr \`date +\%s\` / 86400 \% 2` -eq 1 ] && <my command>

This will run this command every monday and by determining whether it's an odd or even day since the unix epoch will run the command

To determine whether a command would run on a specific day use the following command:

expr `date +%s -d "today"` / 86400 \% 2

a 1 means it will run a 0 means it won't. Adjust the -eq 1 to -eq 0 to adjust the day the command runs on.