Segmentation fault
The shortest code that will return a segmentation fault (SIGSEGV) but compiles properly with "gcc -Wall -Werror -O"
int main(){return main();}
26 characters.
EDIT:
int main(){goto*0;}
19 characters.
Written by Stanley Tan
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8 Responses
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Hate to disagree:
int main(){raise(11);}
Or a more standardized version:
#include<signal.h>
int main(){raise(SIGSEGV);}
There is also the potential for a good optimizing compiler to convert your tail recursion into loop. Thus potentially sending you into an infinite loop rather than a crash. Theoretically an empty loop (with no side affects) may also be optimized away to make your code do nothing and thus just return.
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@lokiastari: It doesn't compile with gcc -Wall -Werror -O
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@khasinski :-) Neither did yours until you added int
. But you need to resolve the main issue in that your may not actually crash with a good compiler. Using g++-4.2
. Examine the output from g++ -Wall -Wextra -Werror -O -S
you will see your tail recursion is been converted into a loop. and thus it will never crash. In older versions you may need to up the optimization level but in 4.2 -O is enough.
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It isn't mine ;) I never posted any, I just like @stnly 's post ;)
Nevertheless the post is still true. I haven't found a way to cause a segfault with gcc cranked up with -Wall -Werror -O shorter than
int main(){return main();}
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If you want a segfault and don't care about passing -W* checks, then the symbol 'main' doesn't need to be a function.
int main;
gcc -o segv -c segv.c
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I think the mac is weird :) I get a Bus error (very similar, but not officially a segfault :) with int main;
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Every infinite recurrent function call will end with a segmentation fault :)
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Wow. I forgot I had this here. Here's one I had going for a while.
int main(){goto*0;}
Enjoy. :)