Check if given executable exists (all shells)
exists() { type -t "$1" > /dev/null 2>&1; }
if exists brew; then
echo 'Homebrew found!'
fi
if ! exists brew; then
echo 'Homebrew not found!'
fiWritten by Adam Stankiewicz
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3 Responses
Which distro do you use? On my Arch Linux and my Centos 6 "which" program does not have "-s" option.
over 1 year ago
·
Hmm. OSX. I've changed the code.
over 1 year ago
·
You could also use which like:
exists() { [ ! -z `which "$1"` ]; }
over 1 year ago
·
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